__SPEED MATHS__

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**5 Number TRICKS: **

**When a number is multiplied by 5 = Half of the number × 10**

**Formula: x×5=Half ofx×10**

- Example:

2Example:

7×5=85

*Half of 17=8.5×10=853

3 Example:

6×5=180

*Half of 36=18×10=1802

4 Example:

36×5=1180

*Half of 236=118×10=11801

5 Example:

364×5=6820

*Half of 1364=682×10=68205

6 Example:

82×5=2910

*Half of 582=291×10=2910

__(____Try yourself 5 digit short tricks with us) __

**When a number is multiplied by 25 = 1/4 of the number × 100**

**Formula: x×25=(x×1/4)×100**

**Example**:

1.18×25=450

*1/4 of the 18=18×14 100=450

2.120×25=3000

*1/4 of the 120=120×14 100=3000

3.249×25=6225

*1/4 of the 249=249×14 100=6225

4.1364×25=34100

*14 of the 1364=1364×14 100=34100

**(Try Yourself another number with 25) **

**When a number is multiplied by 125 = 18 of the number × 1000**

**Formula x×125=(x×1/8)×1000**

**Example: **

1. 5 × 125 = 625

*18 of the 5 = 5 × 1/8 × 1000 = 625

2. 18 × 125=18 × 1/8 ×1000

=2.25 × 1000

=2250

3. 400 × 125=400 × 1/8 ×1000

=50 × 1000

=50000

4. 289 × 125 = 289 × 1/8 × 1000

= 36.125 × 1000

= 36123

__Multiplication by 11__

__Multiplication by 11__

__Tricks 1.__

**33 × 11 = 363**

**Tricks 2:**

**38 × 11 = 418**

**52 × 11=572 (Same as example 1)**

**Tricks 3.**

**3 or <3 digit number **

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## Calendar Test :

**Days code :**

**Months code :**

**Years Code :**

### Q. 1. What was the day of the week on 26th January 1947 ?

Step 1. Last two digit of the year - 47.Step 2. Above digit is divided by 4 : 47/4= 11 (using this method)Step 3. Take the Date - 26Step 4. Take the code for the month - 00 (for January )Step 5. Take the code for year : 00 ( for 1900 to 1999 is 0)

________________________________Sum= 84Step 5.- sum/7=84/7=7*12+0 now remaining number is Zero.

Therefore, code "0" is referes to Sunday. So, 26th January 1974 was on Sunday{alertSuccess}

### Q. 2. What was the day of the week on 5th October 2016 ?

Solution:

Step 1. Last two digits of the year - 16

Step 2. Divided by 4 - 04

Step 3. Take the date - 05

Step 4. Take the code for month ( October ) - 00

Step 5. Take the code for year ( 2016 ) - 06

Step 6. Sum/7=31/7=7*4+3Code 3 refers to wednesday.

So, 5th October 2016 on Wednesday.

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**Condition for Leap Year:**

### Q. 3. What was the day of the week on 24 February 2012 ?

Solution:

Last two digits of the year - 12.

Divided by 4 - 03

Take date - 29

Code for month - 03

Code for year - 06

Sum = 53

Now, Sum/7 = 53/7= 7×7+4

In case of leap year, code for the date= Reminder - 1 =4-1=3

Code 3 represents Wednesday.

So 29th February 2012 was on Wednesday.

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